10000x+10000x^2-12500=0

Solution for 10000x+10000x^2-12500=0 equation:

10000x+10000x^2-12500=0

a = 10000; b = 10000; c = -12500;
Δ = b2-4ac
Δ = 100002-4·10000·(-12500)
Δ = 600000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{600000000}=\sqrt{100000000*6}=\sqrt{100000000}*\sqrt{6}=10000\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10000)-10000\sqrt{6}}{2*10000}=\frac{-10000-10000\sqrt{6}}{20000}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10000)+10000\sqrt{6}}{2*10000}=\frac{-10000+10000\sqrt{6}}{20000}
$